Word | Frequency | Number of right neighbors | Number of left neighbors | Ratio |
---|---|---|---|---|
واكد | 1321 | 82 | 1 | 82.0000 |
اجل | 1497 | 115 | 2 | 57.5000 |
وأشار | 1522 | 49 | 1 | 49.0000 |
وذكرت | 959 | 47 | 1 | 47.0000 |
واعتبر | 779 | 44 | 1 | 44.0000 |
أجل | 2718 | 210 | 5 | 42.0000 |
ويقول | 1832 | 113 | 3 | 37.6667 |
ونقلت | 1098 | 36 | 1 | 36.0000 |
وكانت | 4190 | 267 | 8 | 33.3750 |
واضاف | 4036 | 99 | 3 | 33.0000 |
ودعا | 847 | 62 | 2 | 31.0000 |
وأشارت | 429 | 29 | 1 | 29.0000 |
وحسب | 415 | 29 | 1 | 29.0000 |
لذا | 403 | 28 | 1 | 28.0000 |
واعلنت | 308 | 28 | 1 | 28.0000 |
وحول | 396 | 28 | 1 | 28.0000 |
وقال | 16957 | 665 | 24 | 27.7083 |
وأكد | 1702 | 83 | 3 | 27.6667 |
وأضاف | 3379 | 82 | 3 | 27.3333 |
وطالب | 415 | 27 | 1 | 27.0000 |
Word | Frequency | Number of right neighbors | Number of left neighbors | Ratio |
---|---|---|---|---|
0 | 1884 | 1 | 74 | 0.0135 |
إضافة | 2941 | 5 | 332 | 0.0151 |
والولايات | 732 | 2 | 49 | 0.0408 |
رضي | 267 | 1 | 22 | 0.0455 |
الأمين | 645 | 2 | 41 | 0.0488 |
مزيد | 517 | 2 | 34 | 0.0588 |
الامين | 480 | 2 | 32 | 0.0625 |
قادرة | 439 | 2 | 31 | 0.0645 |
اعتبارا | 231 | 1 | 15 | 0.0667 |
العديد | 1521 | 5 | 71 | 0.0704 |
للولايات | 640 | 3 | 41 | 0.0732 |
المزيد | 925 | 4 | 51 | 0.0784 |
المدعومة | 123 | 1 | 12 | 0.0833 |
صلى | 634 | 2 | 24 | 0.0833 |
1. | 105 | 1 | 12 | 0.0833 |
؟ | 1448 | 4 | 47 | 0.0851 |
مليار | 3872 | 23 | 269 | 0.0855 |
سلبا | 102 | 1 | 11 | 0.0909 |
خادم | 213 | 1 | 11 | 0.0909 |
بوسع | 185 | 1 | 11 | 0.0909 |
In this subsection, we compute the ratio of the number of right neighbors and the number of left neighbors. Again, we look for words with extreme ratios:
Data for first table:
select word,w.freq,aa.cnt, bb.cnt,aa.cnt/bb.cnt as r from words w, (select w1_id,count(c.w2_id) as cnt from co_n c where w1_id>100 group by w1_id) aa, (select w2_id,count(c.w1_id) as cnt from co_n c where w2_id>100 group by w2_id) bb where w_id=aa.w1_id and aa.w1_id=bb.w2_id order by r desc limit 20;
Diagram data:
select aa.cnt, bb.cnt from (select w1_id,count(c.w2_id) as cnt from co_n c where w1_id>100 group by w1_id) aa, (select w2_id,count(c.w1_id) as cnt from co_n c where w2_id>100 group by w2_id) bb where aa.w1_id=bb.w2_id;
5.1.7.1 Number of NN co-occurrences vs. Frequency I
5.1.7.2 Number of NN co-occurrences vs. Frequency II